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The diameter of a hole is given as 50.00+0.015-0.0 mm. The upper limit on the dimensions in mm, of the shaft for achieving maximum interference of 50 microns is _______.
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- 10 microns
- 30 microns
- 40 microns
- 28 microns
Correct Option: B
In worst assembly condition, clearance will maximum
Clearance (max) = Max hole dia – Minimum shaft diameter
= 20.025 – 19.995 = 0.030 = 30 microns
