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A tiger is 50 leap of its own behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 metre and 5 metre per leap respectively, what distance in meters will the tiger have a run before it catches the deer?
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- 500 ms
- 1200 ms
- 800 ms
- 600 ms
Correct Option: C
Tiger – 1 leap ⇒ 8 meter
Speed = 5 leap/hr = 40m/min
Deer → 1 leap = 5 meter
speed = 4hr = 20m/min
Let at time ‘t’ the tiger catches the deer.
∴ Distance travelled by deer + initial distance between them
50 × 8 ⇒ 400m = distance covered by tiger.
⇒ 40 × t = 400 + 20t
| ⇒ t = | = 20 min | 200 |
⇒ total distance ⇒ 400 + 20 × t = 800 ms
