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The product of three integers X, Y and Z is 192. Z is equal to 4 and P is equal to the average of X and Y. What is the minimum possible value of P?
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- 6
- 9.5
- 7
- 8
Correct Option: C
Given product of three integers, X.Y.Z = 192
Given: Z = 4
| ∴ X.Y = | = 48 | 4 |
| ∵ P = | 2 |
Now,
Possible value of (X, Y) are (48, 1), (24, 2), (16, 3), (12, 4), (8, 6)
| So, (P)min< | = 7 | 2 |
So, min value of P is 7.
