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  1. The product of three integers X, Y and Z is 192. Z is equal to 4 and P is equal to the average of X and Y. What is the minimum possible value of P?
    1. 6
    2. 9.5
    3. 7
    4. 8
Correct Option: C

Given product of three integers, X.Y.Z = 192
Given: Z = 4

∴ X.Y =
192
= 48
4

∵ P =
X + Y
2

Now,
Possible value of (X, Y) are (48, 1), (24, 2), (16, 3), (12, 4), (8, 6)
So, (P)min<
8 + 6
= 7
2

So, min value of P is 7.


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