
The product of three integers X, Y and Z is 192. Z is equal to 4 and P is equal to the average of X and Y. What is the minimum possible value of P?

 6
 9.5
 7
 8
Correct Option: C
Given product of three integers, X.Y.Z = 192
Given: Z = 4
∴ X.Y =  = 48  
4 
∵ P =  
2 
Now,
Possible value of (X, Y) are (48, 1), (24, 2), (16, 3), (12, 4), (8, 6)
So, (P)_{min<}  = 7  
2 
So, min value of P is 7.