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How many 1's are present in the binary representation of—
3 × 512 + 7 × 64 + 5 × 8 + 3?
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- 8
- 9
- 10
- 11
Correct Option: B
3 × (8)3 + 7 × (8)2 + 5 × 81 + 3 × 8º means 512, 64, 8 and 1 can be written as power of 8. The proceeding number is translatable to an octal number (3 7 5 3)8 = (011 111 101 011)2 Number of 1 = 9. Hence alternative (B) is the correct answer.
