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The minimum Boolean for the following circuit is—
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- AB + AC + BC
- A + BC
- A + B
- A + B + C
Correct Option: A
If any of the 1, 2 or 3 switch are close, output Y will be 1.
Hence form OR function so output,
Y = A (B + C) + AB + (A + B) C
or Y = AB + AC + AB + AC + BC
or Y = AB + AC + BC
Hence alternative (A) is the correct answer.
