Implement Y = A + BC + AC requires minimum number of NAND

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Implement Y = A + BC + AC requires minimum number of NAND gate are—

1. 4
2. 6
3. 5
4. 3

Correct Option: A

Given,

or Y = A + AC + BC
or Y = A (1 + C) + BC
or Y = A + BC
So, the minimum number of NAND gates requirement is 4. Hence alternative (A) is correct choice.