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AB + A′C + BC is equivalent to—
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- AB + BC
- AB + A′C
- A′C + BC
- AC
Correct Option: B
AB + A′C + BC
= AB (C + C′) + A′C (B + B′) + BC (A + A′)
∴ C + C′ = B + B′ = A + A′ = 1
= ABC + ABC′ + A′CB + A′CB′ + BCA + BCA′
= ABC + ABC′ + A′CB + A′CB′ + BCA
= AB (C + C′) + A′C (B + B′) + BCA
= AB + A′C + BCA
= AB (C + 1) + A′C
= AB + A′C
