Correct Option: B

XOR

F1 = AB
F2 = (ABA)′ = AB + A′
F3 = (ABB)’ = AB + B′
Y=F2 F3 = (AB + A′) (AB + B′)′
= (AB + A′B′)′
= A′B + AB′
= X OR gate.
Hence alternative (B) is the correct answer.