F1 = 0 (since both the input have same value i.e., A ⊕ A = AA + AA = 0) F2 = A (since F1 ⊕ A ⇒ 0 ⊕ A = 0A + A0 = A F3 = 0 (since F2 ⊕ A ⇒ A ⊕ A = AA + AA = 0 Hence alternative (B) is the correct answer.
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