Correct Option: D

The given chip arrangement

Given that CHIP Select (CS) is active high.
From figure we conclude that For chip #1 → A₈ should be 1 and A₉ should be 0 in order to make the chip select enable active.
For chip #2 → A8 should be 0 and A9 should be 1 in order to make the chip select enable active.
Given A₁₀ – A₁₅ not used it, we can use these bits either 0 or 1.
Now, this problem is further solved by applying Hit and Trial method
Add. lines: A₁₅ A₁₄ A₁₃A₁₂ A₁₁ A₁₀A₉ A₈ A₇ A₆ A₅A₄ A₃ A₂ A₁ A₀
Chip #1: X X X X X X 0 1 X X X X X X X X
Chip #2: X X X X X X 1 0 X X X X X X X X

Option (A) → 0100: for Chip #1 is possible
    [0000 0001 0000 0000]
    02FF: for Chip #2 is possible
    [0000 0010 1111 1111]

Option (B) → F900: for Chip #1 is possible
    [1111 1001 0000 0000]
    FAFF: for Chip #2 is possible
    [1111 1010 1111 1111]

Option (C) → 1500: for Chip #1 is possible
    [0001 0101 0000 0000]
    16FF: for Chip #2 is possible
    [0001 0110 1111 1111]

Option (D) → F800: for Chip #1 is not possible
&nsbp;&nsbp;F9FF: for Chip #2 is not possible]

Hence alternative (D) is correct choice.