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In a broadcast transmitter, the RF output is represented as
e(t) = 50 [1 + 0·89 cos 5000 t + 0·30 sin 9000t] cos (6 × 106t) volt
What are the sidebands of the signals in radians?
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- 5 × 103 and 9 × 103
- 5·91 × 106 , 5·995 × 106 , 6·005 × 106 and 6·009 × 106
- 4 × 103 , 1·4 × 104
- 1 × 106 , 1·1 × 107, 3 × 106 , 1·5 × 107
Correct Option: B
The given equation. e(t) = 50[1 + 0·89 cos 5000 t + 0·30 sin 9000t] cos (6 × 106t) volt
Let 5000 = ωm1 or ωm1 = 0·005 MHz
9000 = ωm2 or ωm2 = 0·009 MHz
6 × 106 = ωc1 or ωc1 = 6 MHz
e(t) = 50[cos ωc1 t + 0·89 cos ωm1t. cos ωc1t + 0·30 sin ωm2t]
Sidebands of the signals are at
ωc1 ± ωm1 and ωc1 ± ωm2, frequency
i.e. (6 ± 0·005) MHz and (6 ± 0·009) MHz
6·005 × 106, 5·995 × 106, 6·009 × 106, 5·991 × 106
Hence alternative (B) is the correct choice.