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					 A PCM system uses a uniform quantizer followed by a 8- bit encoder. The bit rate of the system is equal to 106bits/s. The maximum message bandwidth for which the system operates satisfactory is—
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                        -  25 MHz 
 
-  6.25MHz 
 
-  12.5 MHz 
 
-  50 MHz 
 
 
-  25 MHz 
Correct Option: B
Let the message bandwidth ω Nyquist rate = 2ω
bandwidth = 2ω × (no. of bits/sec taken for quantization) 
= 2ω × 8 = 16ω bits/sec 
given that bit rate = 108 bits/sec 
Now, 108 = 16ω
| ω = | ×100 = 106 = 6.25 MHz | |
| 16 | 
 
	