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  1. In figure given below
    m(t) =
    2 sin 2πt
    t

    s(t) = cos 200 πt and n(t) =
    sin 199 πt
    . The output y(t)
    t


    1. sin 2πt
      2t
    2. sin 2πt
      +
      sin πt
      cos 3πt
      2tt
    3. sin 2πt
      +
      sin 0.5πt
      cos 1.5πt
      2tt
    4. sin 2πt
      +
      sin πt
      cos 0.75πt
      2tt
Correct Option: C

m(t) s(t) = y1(t)
=

=
2 sin (2πt) cos(2πt)
t

or
y1(t) =
2 sin (2πt) cos(2πt)
t
...(A)
y2(t) = y1(t) + n(t)
=
sin 202πt - sin 198πt
+
sin 198πt
tt
...(B)
Now y(t) = y2(t).s(t)
=
[sin 202πt - sin 198πt + sin 199πt]cos 200πt
t

or
y(t) =
1
[sin (402πt) + sin(2πt) − {sin(389πt) − sin2πt} + sin(399πt) − sin(πt)]
2t
...(C)
After filtering equation (C) through LPF with cut-off frequency 1 Hz we get
or
y(t) =
sin (2πt) + sin (2πt) − sin (πt)
2t

or
y(t) =
sin (2πt) + 2sin (0.5t) cos(1.5πt)
2t

or
y(t) =
sin (2πt)
+
sin 0.5t
cos 1.5πt
2tt

Hence alternative (C) is the correct choice.



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