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Let message signal m(t) = cos (4π 103t) and carrier signal c(t) = 5 cos (2π 106)t are used to generate a FM signal. If the peak frequency deviation of the generated FM signal is three times the transmission bandwidth of the AM signal, then the coefficient of the term, cos [2π(1008 × 103t)t] in the FM signal would be—
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- 5J4 (3)
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(3)5 J8 2 -
(4)5 J8 2 - 5 J4(6)
Correct Option: D
Given that, m(t) = cos (2π × 103t)
c(t) = 5 cos (2π × 106t)
and
Δf = 3 (transmission bandwidth)
Δf = 3(2fm) = 6fm
Now, modulation index
β = | = | = 6 | ||
fm | fm |
The FM signal is represented in terms of Bessel function as
SFM(t)=Ac ∑∞ n = – ∞ Jn (β) cos (ωc + nωmt)
given that
SFM (t) = [cos 2π (10008 × 103t)] or
SFM (t) = cos[(2π × 106 + 8π × 103)t]
= Ac ∑∞n = – ∞ Jn (β) cos(ωc + ωm)t
n = 4
Thus coefficient, Ac Jn (β) = 5j4 (6)