The Nyquist sampling rate for the signal g(t) = 10 cos (50πt)

The Nyquist sampling rate for the signal g(t) = 10 cos (50πt) cos² (150 πt) where ‘t ’ is in seconds is—

1. 150 samples per second
2. 200 samples per second
3. 300 samples per second
4. 350 samples per second

Given
g(t) = 10 cos(50πt) cos² (150πt)

= 10 cos(50πt)	[1 + cos92.150πt]
	2

= 5 cos(50πt) + 5 cos (50πt) cos (300πt)

= 10 cos(30πt) +	5	[cos (350πt) + cos (250πt)]
	2

Hence
fm_max = 175Hz
So Nyquist sampling rate
2fm_max = 2 × 175 = 350 sample per second.