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Six independent low pass signals of bandwidth 3ω, ω, ω, 2ω, 3ω, and 2ω Hz are to be time division multiplexed on a common channel using PAM. To achieve time, the minimum transmission bandwidth of the channel should be kHz—
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- 3ω
- 6ω
- 12ω
- 24ω
Correct Option: C
The commutator in TDM (Time Division multiplication) has to be rotated a speed twice that of highest bandwidth i.e. 3ω × 2 = 6ω
channel capacity = 2 x highest Bandwidth
= 2 × 6ω Hz = 12ω Hz