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Following equations hold for time-varying fields—
(i)∇ × E = − ∂B ∂t
(ii)E = − ∇ − ∂A ∂t
(iii)∇2V + ∂ (∇⋅A) = −ρv ∂t ε
(iv)→ → B = ∇ × A
(v)→ → ∇ × H = J + ∂E ∂t
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- Both V and →A are completely defined and thus can be evaluated
- V is completely defined but not →A
- →A Is completely defined but not V
- Both →A and V are not completely defined
Correct Option: A
Both V and →A are completely defined and thus can be evaluated.
