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The expression for B, given that in free space E = 15 cos (6π × 108 t – 2πz) ix V/m is—
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- 5 × 10–8 cos (6π × 108 t – 2πz) iy
- – 90π × 108 sin (6π × 108 t – 2πz) ix
- – 45 × 108 sin (6π × 108 t – 2πz) iy
- 5 × 10–8 [cos (6π × 108 t – 2πz) iy – sin (6π × 108 t – 2πz) iz]
Correct Option: A
The given wave is travelling in the + z direction (because of the presence of the term – 2 πz) and E is entirely in the x-direction. Now E and H direction gives the direction of travel of tower. It is concluded, therefore, that H must be in + y direction.
ix × iy = iz
Further, we know that
| H | = | and B = µ0 H | |||
η |
η = | √ | or | B | = | ||
ε0 | √µ0/ε0 |
= | ![]() | ∵ = V | ![]() | |
√µ0∈0 |
B = | |
3 × 108 |
or
B = 5 × 10-8 cos (6π × 108 t – 2π z) iy Wb/m2