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The positive RF peaks of an AM voltage rise to a maximum value of 12V and drop to a minimum value of 4V. The modulation index assuming single tone modulation is—
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- 3
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1 3
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1 4
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1 2
- 3
Correct Option: D
Given, Vmax = 12V and Vmin = 4V, we know that modulation index.
| μ = | Vmax - Vmin |
| Vmax + Vmin |
| = | 12 - 4 | = | 8 | = | 1 |
| 12 + 4 | 16 | 2 |