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The close-loop transfer function of a control system is given by
For the input r (t) = sin t, the steady state value of C(t) is equal to—C(s) = 1 R(s) 1 + s
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1 cos t √2
- 1
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1 sin t √2
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1 sin t (1-π/4) √2
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Correct Option: D
Given
= | ||
R(s) | 1 + s |
r (t) = sin t
In order to calculate the C(t), we will calculate the magnitude and phase by the term 1/(1 + s)
Mag. of | ![]() | ![]() | = | = | |||
1 + s | √1 + 1 | √2 |
Phase of | ![]() | ![]() | = - tan-1 | ![]() | ![]() | = | |||
1 + s | 1 | 4 |
so,
C(t) = | sin | ![]() | t - | ![]() | ||
√2 | 4 |