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  1. The closed-loop transfer function of a control system is given by
    C(s)
    =
    2(s - 1)
    R(s)(s + 2)(s + 1)

    For a unit step input the output is—
    1. – 3e–2t + 4e– 1 – 1
    2. – 3e–2t – 4e–t + 1
    3. zero
    4. infinity
Correct Option: A

Given r (t) = 1 then R (s) = 1/s

C(s)
=
2 (s - 1)
R(s)(s + 2)(s + 1)

C(s) = R(s).
2 (s - 1)
s(s + 2)(s + 1)

=
0.2 (s - 1)
s(s + 2)(s + 1)

C(s) =
A
+
B
+
C
ss + 1s + 2

A =
2 (s + 1)
|s=0 = -1
(s + 1)(s + 2)

B =
2 (s - 1)
|s=1 = 4
s(s + 2)

C =
2 (s - 1)
|s=2 = -3
s(s + 1)

on putting the value of A, B, C we get
C(s) =
-1
+
4
-
3
ss + 1s + 2

Taking inverse Laplace transform, we get
C (t) = – 1 + 4e– t – 3e– 2t



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