-
The transfer function of a closed loop system is 1/1 + sT. The input to this system is t u(t). The output would track this system, but the error would be—
-
- 0
- T2
- T
- T/2
- 0
Correct Option: C
Given that
| = | ||
| R(s) | 1 + sT |
r(t) = tu(t)
then
R (s) = 1 s/2
E (s) = R (s) – C (s)
| - | |||
| s2 | s2 | sT + 1 |
| = | |
| s2(sT + 1) |
| = | |
| s(sT + 1) |
ess = s → 0Lim . s. E (s)
| = s → 0Lim s· | = T | |
| s(sT + 1) |
