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Transfer function G(s) has the pole-zero as shown in the given figure. Given that the steady state gain is 2, the transfer function G(s) will be given by—
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2(s + 1) s2 + 4s + 5
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5(s + 1) s2 + 4s + 4
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10(s + 1) s2 + 4s + 5
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10(s + 1) (s + 2)2
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Correct Option: C
Here there are 2 pole and 1 zero.
Let the transfer function G (s) of the type
G (s) = | |
(s + 2 + j) (s + 2 – j) |
or G (s) = | = | ||
(s + 2)2 – j2 | s2 + 4s + 5 |
Also given that steady state gain is 2.
i.e., G (0) = 2 = | |
02 + 4·0 + 5 |
or
K = 10
Now,
the T.F. G (s) = | |
s2 + 4s + 5 |
