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The state and output equation of a system are as under state equation:
x1 (t) = 0 1 x1 (t) + 0 u(t) x2 (t) -1 -2 x2 (t) 1
AndC(t) =[1 1] x1 (t) x2 (t)
The system is—
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- neither state controllable nor output controllable
- state controllable but not output controllable
- output controllable but not state controllable
- both state controllable and output controllable
Correct Option: B
Given state equation:
![]() | ![]() | = | ![]() | ![]() | ![]() | ![]() | + | ![]() | ![]() | u(t) | |||||||
x2 | (t) | -1 | -2 | x2 | (t) | 1 |
C(t) = [1 1] | ![]() | ![]() | ||
x2 | (t) |
Here,
A = | ![]() | ![]() | ||
-1 | -2 |
B = | ![]() | ![]() | ||
1 |
C = [1 1]
Check for controllability
AB = | ![]() | ![]() | ![]() | ![]() | = | ![]() | ![]() | |||||
-1 | -2 | 1 | -2 |
∴ QC = [B: AB] = – 1, which is non-singular.
Hence, the state equation is controllable.
Check for observability :
A = | ![]() | ![]() | ||
-1 | -2 |
then
AT = | ![]() | ![]() | ||
1 | -2 |
C = [1 1]
then
CT = | ![]() | ![]() | |
1 |
Now,
ATCT = | ![]() | ![]() | ![]() | ![]() | |||
1 | -2 | 1 |
= | ![]() | ![]() | |
-1 |
θ0 = [CT : AT CT]
ATCT = | ![]() | ![]() | ||
1 | -1 |
= 0 i.e., singular.
Hence given system equation is not observable.
Therefore alternative (B) is the correct choice.