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For the circuit shown below, find the value of R for which I1 = 2A—
-
- 80Ω
- 20Ω
- 40Ω
- None of these
- 80Ω
Correct Option: C
The given circuit
The given circuit can be modified as shown below
The current in 200Ω resistance is 4 – 2 = 2A.
So, the voltage drop across 200Ω resistance
= 2 × 200 = 400V.
Now,
400 = 160 × I1 + I1 × R
or
400 = 160 × 2 + 2 × R
or
R = | = 40Ω | |
2 |
Hence alternative (C) is the correct choice.