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What is the value of the parameter h12 for the 2-port network shown in the figure given above?
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- 0·125Ω
- 0·167Ω
- 0·250Ω
- 0·625Ω
- 0·125Ω
Correct Option: C
The given network 
We know that
| h12 = | /I1 = 0 | |
| V2 |
The given network can be modified as:
Applying KCL at node A
| + | + | = 0 | |||
| 4 | 8 | 4 |
or
| VA |  | + | + |  | = | + | |||||
| 4 | 8 | 4 | 4 | 4 |
or
| VA = | + | |||
| 8 | 4 | 4 |
or
| VA = V2 + V1 …. . . . . . (i) | |
| 2 |
Again by applying potential divider rule
| V1 = V1 × | = | ||
| 2 | 2 |
or
VA = 2V1
Now
| .2V1 = V2 + V1 | |
| 2 |
or
4 V1 = V2
or
| = | = h12 = 0·250Ω | ||
| V2 | 4 |
Hence alternative (C) is the correct choice.
