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For the following circuit, a source of V1(t) = e– 2t is applied. What will be the V2 (t)—
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- 2e–2t– e–t
- e– t
- e– t – e–2t
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e–2t 2
Correct Option: A
The given circuit 
From figure
| V2(s) = V1(s) | = V1(s) | |||
| s | ||||
| + 1 | ||||
| s | ||||
| = V1(s) | |
| (1 + s) |
where,
| = V1(s) | |
| s + 2 |
[Given V1(t) = e–2t]
Now,
| V2 (s) = | × | = | + | ||||
| (s + 2) | (s + 1) | s + 1 | s + 2 |
| = - | + | ||
| s + 1 | s + 2 |
or
V2(t) = 2e–2t – e–t
Hence alternative (A) is the correct choice.
