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A dc circuit shown below has a voltage V, a current source I and several resistors. A particular resistor R dissipates a power of 4W when V alone is active. The same resistor dissipates a power of 9W when I alone is active. The power dissipated by R when both sources are active will be—
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- 1W
- 5W
- 13W
- 25W
- 1W
Correct Option: D
The given circuit:
Resistive network Applying superposition theorem (since here one energy source is acting at a time)
● When only voltage source is active:
V2/R = 4W = I2R
Let R = 1Ω
Assume I1 = I = 4 = 2A
● When only current source is active
I2R = 9W
or
I2 = 9W
Assume
I22 = I2 = 9
or
I2 = 3A
Since current flowing in both the case follow the same direction. Therefore, net current will add up.
So,
I = I1 + I2 = 2 + 3 = 5A
Now, the power dissipated by R when both sources are active will be:
P=I2R = 52.1 = 25W
Hence alternative (D) is the correct choice.