Correct Option: D

The given circuit:

From figure we conclude that the magnitude of current dependent source is 2 times that of 6Ω branch. It means resistance of dependent sources is half of the 6Ω, i.e., 3Ω

I =	V	=	24	=	24	= 12A
	Req		3|| 6		2

Now, the power delivered by 24V source

= VI = 24 × 12 = 288W.
Alternative Method:
From figure, I = I_R + 2I_R = 3I_R
Applying KVL in the input loop
24 = 6I_R
or
I_R = 4A
and
I = 3I_R = 3 × 4 = 12A
Now, power delivered by 24V source is:
VI = 24 × 12 = 288W.