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In the circuit shown below, what is the voltage across 5Ω resistor i.e. (V1 – V2)
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- – 30V
- 30V
- 1250V
- – 1250V
- – 30V
Correct Option: B
The given circuit: 
From figure, KCL at node 1
| + | = 176 …. .......(i) | ||
| 7 | 5 |
Again KCL at node 2
| + | = 110 …. .......(i) | ||
| 10 | 5 |
From equation (i) and (ii), we get
V1 = 1190V and V2 = 1160V
Now, V1 – V2 = 1190 – 1160 = 30V
