Correct Option: A

The given circuit:

From above circuit,
X_L = 2πf L = 2 × 3·14 × 100 × 70 × 10^–3
= 43·98Ω
Now,
Z_eq = (40 + j43·98)Ω
Current,

I =	Vs	=	30 0°
	Zeq		40 + j43·98

≈ 0·5 – 47·7°A
Thus, we conclude that current lags behind the applied voltage by 47·7°. Hence the phase angle between voltage and current, θ = 47·7°.