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For the circuit shown below, the voltage across 30Ω resistor is 45 volts. The reading of ammeter A will be—
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- 10A
- 3·5A
- 22·4A
- 28A
- 10A
Correct Option: B
The given circuit:
From figure,
I30Ω = | = 1·5A | |
30 |
Voltage across 10Ω resistance is
= 1·5 × 10 = 15V
Now,
VAB = 15V + 45V = 60 V
Current in branch
CD = | = 2A | |
30Ω |
Now, current in ammeter
= 1·5 + 2 = 3·5 A