In figure, the admittance values of the elements in siemens

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In figure, the admittance values of the elements in siemens are Y_R = 0·5 + j0, Y_L = 0 – J1·5, Y_C = 0 + j0·3 respectively. The value of I as a phasor when the voltage E across the elements is 10 ∠ 0° V is—

1. 1·5 + j0·5
2. 5 – j18
3. 0·5 + j1·8
4. 5 – j12

Correct Option: D

The given figure:

I = V Y_eq
where, Y_eq = Y_R + Y_L + Y_C
= 0·5 + j0 + 0 – j1·5 + 0·j 0·3
= 0·5 – j1·2
Now, I = 10 0° (0·5 + j1·2)
or
I = 5 – j12
Hence alternative (D) is the correct choice.