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The voltage across the 1 kΩ resistor between A and B of the network shown in the given figure is— 10 V 2k Ω 2k Ω 2A 1k Ω A B (A) (B) 14 3 V (C) (D) 26 3 V
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- 12 V
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14 V 3 - 10 V
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26 V 3
Correct Option: B
In order to calculate the voltage drop between A and B Apply Superposition theorem.
Case I. When 10 V source is taken circuit becomes b
| VAB = | . 10 = | V (say V1) | 1 + 2 | 3 |
Case II. When current source is taken circuit becomes current in branch AB
| I = 2 × | = | amp. | 2 + 1 | 3 |
| Voltage drop across AB = | × 1 = | V (say V2) | 3 | 3 |
Net voltage drop between
| A and B = V1 + V2 = | + | = | V | 3 | 3 | 3 |
