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S is in position (a) for a long time. S moved to position (b) at t = 0—, At t = 0+, the values of IC and VL are—
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- – 5, 0
- 5, 0
- 0, 4
- – 2, 3
Correct Option: A
Where switch S is in position (a) for a long time in steady state in opened L is short. The circuit looks like 
| l L = 5 × | = 4A | 4 + 1 |
VC (0–) =VC (0+) = 4 × 1 = 4 V
As the switch is moved to position (b) current through 4 Ω resistor
| =4 | = 1 A | 4 |
∴ Current through capacitor = – (1 + 4) = – 5 A
VL = 4 × 1 = 4
∴ as the two voltage are in opposite sign
so VL = 0 V
