In the circuit Vs = cos 2t. The value of C is chosen so

In the circuit V_s = cos 2t. The value of C is chosen so that I from V_s is in phase with V_s. Then I_c leads I_L by an angle given by—

Given that V_s = cos 2t
I _C = V_s . SC
or I_C = cos ωt. s.1

or I_C = cos 2t. J2 (∵ ω = 2)
or I_C = 2 V_s ∠ 90° .....(1)

I _L =	V_s	=	V_s	=	V_s	=	V_s
	2 + L_s		2 + s		2 + jω		2 + j2

=	V_s	=	V_s
	2(1 + j)		2√2∠ 45°

=	V_s	∠ – 45° .....(2)
	2√2

from eq. (1) and (2) it is clear that the phase difference between the Ic and IL = [90 – (– 45°)] = 135°