The Thevenin equivalent voltage Vm appearing between the

Home » Network Theory » Network Elements and the Concept of Circuit » Question

The Thevenin equivalent voltage V_m appearing between the terminals A and B of the network shown is given by—

1. J 16 (3 – J 4)
2. J 16 (J 3 + 4)
3. J 6 (3 + J 4)
4. J 6 (3 – J 4)

Correct Option: B

If we see the given network carefully, we get that there are two extra reduntant elements present in the circuit are J2, – J6. Because voltage at these element is independent.
Now apply potential divider rule between 3, J4 element.

V_m =		J4	× 100 ∠ 0° =	J4 × 100 ∠ 0°		(3 – J4)
		3 + J4		3 + J4		3 - J4

= 16 (4 + 3J)