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The two transistors in figure are identical. If β = 25, the current Ic2 is—
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- 28 µA
- 23·2 µA
- 26 µA
- 24 µA
Correct Option: B
The given figure (i.e., fig)
From figure Iref = 25 µA
Since both the transisors are identical
Therefore IB1 = IB2 = IB & VBE1 = VBE2 = VBE
Now, Iref = IB1 + IC1 + IB2 = IB + βIB + IB = (β + 2) IB
and IC2 = βIB2 = BIB1 = βIB = | (β + 2) |
or IC2 = 25· | = 23·2 µA | (25 + 2) |
Hence alternative (B) is the correct choice.
