In the circuit shown below V1 = 2·7 V, VBE = 0·7 V and

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In the circuit shown below V₁ = 2·7 V, V_BE = 0·7 V and β >> 1. The g_m of the transistor is—

1. 200 m mho
2. 400 m mho
3. 200 ohms
4. 400 ohms

Correct Option: B

The given circuit (i.e., fig)
Given, V₁ = 2·7 V, V_BE = 0·7 V and β >> 1 means I_B ≈ OA
Applying KVL to the input section, we get
V₁ – V_BE – I_C · 200 = 0
or 2·7 – 0·7 – I_C · 200 = 0

or I_C =	2	A
	200

Now, g_m =	I_C	=	2/200 A	= 400 mA/ V
	V_T		25 mV

or g_m = 400 m mho
Hence alternative (B) is the correct choice.