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A silicon sample contains acceptor atoms at a concentration of Na = 5 × 1015 cm–3. Donor atoms are added forming and n-type compensated semiconductor such that the Fermi level is 0.215 eV below the conduction band edge. The concentration of donors atoms added are—
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- 1.2 × 1016 cm–3
- 4.6 × 1016 cm–3
- 3.9 × 1012 cm– 3
- 2.4 × 1012 cm– 3
Correct Option: A
We know that, n0 = Nd – Na = Nc e – {( EC – EF) / kT}
for Si, Nc = 2.8 × 1019 cm–3
given Na = 5 × 1015 cm–3
Now, Nd = Na + Nc e – {( EC – EF) / kT}
or Nd = 5 × 1015 + 2.8 × 1019 e – (215eV / 26 x 10-3eV)
{˙.˙ given that Fermi level is 0.215 eV below the or Nd = 1.19 × 1016 cm–3 conduction band i.e. Ec – EF = 0.215 eV}
Hence alternative (A) is the correct choice.