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What will be the starting address of memory chip, given that memory address of last location of an 8K byte memory chip is FFFFH—
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- DEFFH
- E000H
- F000H
- None of these
Correct Option: B
8 K byte = 1024 × 8 = 8192 memory location (i.e., from 0 – 8191)
Now binary representation of decimal 8191 in 16-bit format is
0001 1111 1111 1111
Given that last location = FFFFH
So, starting address
FFFFH = 1111 1111 1111 1111
–8 K byte = 0001 1111 1111 1111
1110 0000 0000 0000
Therefore, Starting address is E000H.
