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Which of the following is the correct output for the program given below?
#include<stdio.h>
int main ( )
{
int fun (int);
int k = fun (20);
printf ("%d\n" , --k) ;
return 0 ;
}
int fun (int i)
{
return (k++) ;
}
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- 19
- 20
- 21
- 18
Correct Option: A
Step 1: int fun(int); Here we declare the prototype of the function fun().
Step 2: int i = fun(20); The variable i is declared as an integer type and the result of the fun(20) will be stored in the variable i.
Step 3: int fun(int k){ return (k++); } Inside the fun() we are returning a value return(k++). It returns 20. because k++ is the post-increment operator.
Step 4: Then the control back to the main function and the value 20 is assigned to variable k.
Step 5: printf("%d\n", --k); Here --k denoted pre-increment. Hence it prints the value 19.
