If energy (E), velocity (V) and time (T) are chosen as the

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If energy (E), velocity (V) and time (T) are chosen as the fundamental quantities, the dimensional formula of surface tension will be :

1. [EV^{– 1}T^{– 2}]
2. [EV^{– 2}T^{– 2}]
3. [E^{– 2}V^{– 1}T^{– 3}]
4. [EV^{– 2}T^{– 1}]

Correct Option: B

Let surface tension s = E^a V^b T^c

MLT^-2	- (ML²T^-2)^a		L		^b	(T)^c
L			T

Equating the dimension of LHS and RHS
ML⁰T^{– 2} = M^aL^{2a + b} T^{– 2a – b + c}
⇒ a = 1, 2a + b = 0, – 2a – b + c = – 2
⇒a = 1, b = – 2, c = – 2
Hence, the dimensions of surface tension are [E V^{– 2} T^{– 2}]