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The frequency of vibration f of a mass m suspended from a spring of spring constant k is given by a relation of the type f = c mx ky , where c is a dimensionless constant. The values of x and y are
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x = 1 , y = 1 2 2 -
x = - 1 , y = - 1 2 2 -
x = 1 , y = - 1 2 2 -
x = - 1 , y = 1 2 2
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Correct Option: D
f = c mx ky ;
Spring constant k = force / length.
[M0 L0 T– 1] = [Mx (MT– 2)y] = [ Mx + y T– 2y]
| ⇒ x - y = 0 , -2y = -1 or y = | ||
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| Therefore , x = - | ||
| 2 |
