If the error in the measurement of radius of a sphere is

If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be :

Error in the measurement of radius of a sphere = 2%

Volume of the sphere =	4	πr³
	3

∴ Error in the volume = 3.	∆r	= 3 × 2% = 6%
	r