If vectors A→ = cos ωtî + sin ωtĵ

If vectors A^{^→} = cos ωtî + sin ωtĵ and B^{^→} = cos ωt î + sin ωt ĵ are functions of time, then the value
2 2

of t at which they are orthogonal to each other is :

Two vectors are
A^{^→} = cos ωtî + sin ωtĵ

B^{^→} = cos	ωt	î + sin	ωt	ĵ
	2		2

For two vectors A^{^→} and B^{^→} to be orthogonal A^{^→} . B^{^→} = 0

A^{^→} . B^{^→} = 0 = cos ωt . cos	ωt	î + sin ωt . sin	ωt	ĵ
	2		2

= cos		ωt -	ωt		= cos		ωt
			2				2

So ,	ωt	=	π	∴ t =	π
	2		2		ω

If vectors A^{^→} = cos ωtî + sin ωtĵ and B^{^→} = cos	ωt	î + sin	ωt	ĵ are functions of time, then the value
	2		2

t =	π
	2ω

t -	π
	4ω