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  1. A particle is moving such that its position coordinate (x, y) are
    ​​(2m, 3m) at time t = 0 ​​
    (6m, 7m) at time t = 2s and ​​
    (13m, 14m) at time t = 5s.
    Average velocity vector (Vav) from t = 0 to t = 5s is :
    1. 1
      (13î + 14ĵ)
      5
    2. 7
      (î + ĵ)
      3
    3. 2(î - ĵ)
    4. 11
      (î - ĵ)
      5
Correct Option: D

Vav =
∆r(displacement)
∆t(time taken)

=
(13 - 2)î + (14 - 3)ĵ
=
11
(î + ĵ)
5 - 05



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