-
A particle is moving such that its position coordinate (x, y) are
(2m, 3m) at time t = 0
(6m, 7m) at time t = 2s and
(13m, 14m) at time t = 5s.
Average velocity vector (V→av) from t = 0 to t = 5s is :
-
-
1 (13î + 14ĵ) 5 -
7 (î + ĵ) 3 - 2(î - ĵ)
-
11 (î - ĵ) 5
-
Correct Option: D
V→av = | ||
∆t(time taken) |
= | = | (î + ĵ) | ||
5 - 0 | 5 |