-
A projectile is fired at an angle of 45° with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is
-
- 60°
-
tan-1 1 2
-
tan-1 √3 2 - 45°
Correct Option: B
H = | = | .....(1) | ||
2g | 4g |
R = | = | |||
g | g |
= | .....(2) | |||
2 | 2g |
∴ tan α = | ||
R / 2 |
= | |||
4g | = | ||
2 | |||
2g |
∴ α = tan-1 | ![]() | ![]() | ||
2 |
