-
A projectile is fired at an angle of 45° with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is
-
- 60°
-
tan-1 
1 
2
-
tan-1 
√3 
2 - 45°
Correct Option: B
| H = | = | .....(1) | ||
| 2g | 4g |
| R = | = | |||
| g | g |
| = | .....(2) | |||
| 2 | 2g |
| ∴ tan α = | ||
| R / 2 |
| = | |||
| 4g | = | ||
| 2 | |||
| 2g | |||
| ∴ α = tan-1 | ![]() | ![]() | ||
| 2 |
