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A ship A is moving Westwards with a speed of 10 km h–1 and a ship B 100 km South of A, is moving Northwards with a speed of 10 km h–1. The time after which the distance between them becomes shortest, is :
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- 5 h
- 5 √2 h
- 10 √2 h
- 0 h
Correct Option: A
V→A = 10(-î)
V→A = 10(ĵ)
V→BA = 10ĵ + 10î = 10 √2 km / h
Distance OB = 100 cos 45° = 50 √2 km
Time taken to reach the shortest distance between A and B
= | = | = 5h | ||
V→BA | 10 √2 |