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300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g = 10 m/s2, work done against friction is
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- 100 J
- zero
- 1000 J
- 200 J
Correct Option: A
Work done against gravity = mg sin θ × d = 2 × 10 × 10 (∵ d sin θ = 10)
= 200 J
Actual work done = 300 J
Work done against friction = 300 – 200 = 100 J
